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	<title>Comments for Newton Excel Bach,  not (just) an Excel Blog</title>
	<atom:link href="http://newtonexcelbach.wordpress.com/comments/feed/" rel="self" type="application/rss+xml" />
	<link>http://newtonexcelbach.wordpress.com</link>
	<description>An Excel blog for engineers and scientists, and an engineering and science blog for Excel users.</description>
	<lastBuildDate>Tue, 21 May 2013 13:13:40 +0000</lastBuildDate>
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		<title>Comment on Beam actions and deflections by Macaulay&#8217;s Method by dougaj4</title>
		<link>http://newtonexcelbach.wordpress.com/2011/11/12/beam-actions-and-deflections-by-macaulays-method/#comment-5544</link>
		<dc:creator><![CDATA[dougaj4]]></dc:creator>
		<pubDate>Tue, 21 May 2013 13:13:40 +0000</pubDate>
		<guid isPermaLink="false">http://newtonexcelbach.wordpress.com/?p=3002#comment-5544</guid>
		<description><![CDATA[Steve - I&#039;m off to bed now (Sydney time is 10 hours ahead of GMT (+9 UK summer time), but if you send me an e-mail to dougaj4 at gmail I&#039;ll send contact  details.]]></description>
		<content:encoded><![CDATA[<p>Steve &#8211; I&#8217;m off to bed now (Sydney time is 10 hours ahead of GMT (+9 UK summer time), but if you send me an e-mail to dougaj4 at gmail I&#8217;ll send contact  details.</p>
]]></content:encoded>
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	<item>
		<title>Comment on Beam actions and deflections by Macaulay&#8217;s Method by Stephen Ward</title>
		<link>http://newtonexcelbach.wordpress.com/2011/11/12/beam-actions-and-deflections-by-macaulays-method/#comment-5543</link>
		<dc:creator><![CDATA[Stephen Ward]]></dc:creator>
		<pubDate>Tue, 21 May 2013 13:08:31 +0000</pubDate>
		<guid isPermaLink="false">http://newtonexcelbach.wordpress.com/?p=3002#comment-5543</guid>
		<description><![CDATA[Thank you, I am trying to edit the SSSpan worksheet as this best suits the side frame of a blast resistant door.  Can I call you to discuss a few questions? 

Regards 

Stephen Ward Director 

[cid:image001.png@01CE562C.A9E8F750] 

Kingsmark Structural Ltd 32 Huntfield Road, Chepstow, NP16 5SA UK 

Tel +44 (0)1291 626656 &#124; Mob +44 (0) 7765 013408]]></description>
		<content:encoded><![CDATA[<p>Thank you, I am trying to edit the SSSpan worksheet as this best suits the side frame of a blast resistant door.  Can I call you to discuss a few questions? </p>
<p>Regards </p>
<p>Stephen Ward Director </p>
<p>[cid:image001.png@01CE562C.A9E8F750] </p>
<p>Kingsmark Structural Ltd 32 Huntfield Road, Chepstow, NP16 5SA UK </p>
<p>Tel +44 (0)1291 626656 | Mob +44 (0) 7765 013408</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Beam actions and deflections by Macaulay&#8217;s Method by dougaj4</title>
		<link>http://newtonexcelbach.wordpress.com/2011/11/12/beam-actions-and-deflections-by-macaulays-method/#comment-5542</link>
		<dc:creator><![CDATA[dougaj4]]></dc:creator>
		<pubDate>Tue, 21 May 2013 13:03:20 +0000</pubDate>
		<guid isPermaLink="false">http://newtonexcelbach.wordpress.com/?p=3002#comment-5542</guid>
		<description><![CDATA[Glad you found it useful Steve.

Feel free to ask if anything isn&#039;t clear, or suggest improvements and/or extensions.]]></description>
		<content:encoded><![CDATA[<p>Glad you found it useful Steve.</p>
<p>Feel free to ask if anything isn&#8217;t clear, or suggest improvements and/or extensions.</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Beam actions and deflections by Macaulay&#8217;s Method by Steve Ward</title>
		<link>http://newtonexcelbach.wordpress.com/2011/11/12/beam-actions-and-deflections-by-macaulays-method/#comment-5541</link>
		<dc:creator><![CDATA[Steve Ward]]></dc:creator>
		<pubDate>Tue, 21 May 2013 12:07:03 +0000</pubDate>
		<guid isPermaLink="false">http://newtonexcelbach.wordpress.com/?p=3002#comment-5541</guid>
		<description><![CDATA[Thank you for posting such a useful tool.  I was wondering how to get excel to add multiple loads on a SS-beam (analysis of a blast resistant door frame) at varying locations and realised the Macaulays method was probably the best way of evaluating the BM from which I could undertake a SDOF analysis of the door as a whole.  Your spreadsheet will be invaluable.]]></description>
		<content:encoded><![CDATA[<p>Thank you for posting such a useful tool.  I was wondering how to get excel to add multiple loads on a SS-beam (analysis of a blast resistant door frame) at varying locations and realised the Macaulays method was probably the best way of evaluating the BM from which I could undertake a SDOF analysis of the door as a whole.  Your spreadsheet will be invaluable.</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Using Goal Seek on Multiple Cells by dougaj4</title>
		<link>http://newtonexcelbach.wordpress.com/2009/07/25/using-goal-seek-on-multiple-cells/#comment-5535</link>
		<dc:creator><![CDATA[dougaj4]]></dc:creator>
		<pubDate>Mon, 20 May 2013 12:33:07 +0000</pubDate>
		<guid isPermaLink="false">http://newtonexcelbach.wordpress.com/?p=1031#comment-5535</guid>
		<description><![CDATA[John - see http://newtonexcelbach.wordpress.com/2013/05/20/using-goal-seek-on-a-multi-column-range/

Any questions, please ask.]]></description>
		<content:encoded><![CDATA[<p>John &#8211; see <a href="http://newtonexcelbach.wordpress.com/2013/05/20/using-goal-seek-on-a-multi-column-range/" rel="nofollow">http://newtonexcelbach.wordpress.com/2013/05/20/using-goal-seek-on-a-multi-column-range/</a></p>
<p>Any questions, please ask.</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Using Goal Seek on Multiple Cells by Using Goal Seek on a multi-column range &#124; Newton Excel Bach, not (just) an Excel Blog</title>
		<link>http://newtonexcelbach.wordpress.com/2009/07/25/using-goal-seek-on-multiple-cells/#comment-5534</link>
		<dc:creator><![CDATA[Using Goal Seek on a multi-column range &#124; Newton Excel Bach, not (just) an Excel Blog]]></dc:creator>
		<pubDate>Mon, 20 May 2013 12:32:04 +0000</pubDate>
		<guid isPermaLink="false">http://newtonexcelbach.wordpress.com/?p=1031#comment-5534</guid>
		<description><![CDATA[[&#8230;] a comment requesting help using my Goal Seek spreadsheet I have modified the macro to allow it to operate on a multi-column [&#8230;]]]></description>
		<content:encoded><![CDATA[<p>[&#8230;] a comment requesting help using my Goal Seek spreadsheet I have modified the macro to allow it to operate on a multi-column [&#8230;]</p>
]]></content:encoded>
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	<item>
		<title>Comment on Using Goal Seek on Multiple Cells by John Pollard</title>
		<link>http://newtonexcelbach.wordpress.com/2009/07/25/using-goal-seek-on-multiple-cells/#comment-5532</link>
		<dc:creator><![CDATA[John Pollard]]></dc:creator>
		<pubDate>Sun, 19 May 2013 21:36:08 +0000</pubDate>
		<guid isPermaLink="false">http://newtonexcelbach.wordpress.com/?p=1031#comment-5532</guid>
		<description><![CDATA[Re.: Goal Seek on multiple cells:-

There is not quite enough explanation for me - I am lost.
I have formula, similar to, but a little more complicated than: z = 1/(sqrt(H^2 + (A-x)^2 + (A-y)^2).
If I can understand the operstion for this situation, I should be able to solve my real problem.
A is a fixed but chosen number.
z is a fixed but chosen number.
x ranges say from -10 to +10 in increments of 1. 
y ranges say from -10 to +10 in increments of 1. 
I would like to find the value of h at each coordinate (x,y) that produces the required constant specified value of z.
And produce a spreadsheet of the values of h for each coordinate (x,y).
Is this description succinct enough?
From your description, I suspect your macro will do the trick.
But I need detailed step by step help!

Regards
John Pollard]]></description>
		<content:encoded><![CDATA[<p>Re.: Goal Seek on multiple cells:-</p>
<p>There is not quite enough explanation for me &#8211; I am lost.<br />
I have formula, similar to, but a little more complicated than: z = 1/(sqrt(H^2 + (A-x)^2 + (A-y)^2).<br />
If I can understand the operstion for this situation, I should be able to solve my real problem.<br />
A is a fixed but chosen number.<br />
z is a fixed but chosen number.<br />
x ranges say from -10 to +10 in increments of 1.<br />
y ranges say from -10 to +10 in increments of 1.<br />
I would like to find the value of h at each coordinate (x,y) that produces the required constant specified value of z.<br />
And produce a spreadsheet of the values of h for each coordinate (x,y).<br />
Is this description succinct enough?<br />
From your description, I suspect your macro will do the trick.<br />
But I need detailed step by step help!</p>
<p>Regards<br />
John Pollard</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Using RC Design Functions &#8211; 1 by Using RC Design Functions – 2 &#124; Newton Excel Bach, not (just) an Excel Blog</title>
		<link>http://newtonexcelbach.wordpress.com/2013/05/10/using-rc-design-functions-1/#comment-5528</link>
		<dc:creator><![CDATA[Using RC Design Functions – 2 &#124; Newton Excel Bach, not (just) an Excel Blog]]></dc:creator>
		<pubDate>Sat, 18 May 2013 07:55:33 +0000</pubDate>
		<guid isPermaLink="false">http://newtonexcelbach.wordpress.com/?p=4838#comment-5528</guid>
		<description><![CDATA[[&#8230;] the previous post we looked at a summary of the functions in the RC Design Functions spreadsheet, and ways of using [&#8230;]]]></description>
		<content:encoded><![CDATA[<p>[&#8230;] the previous post we looked at a summary of the functions in the RC Design Functions spreadsheet, and ways of using [&#8230;]</p>
]]></content:encoded>
	</item>
	<item>
		<title>Comment on Using RC Design Functions &#8211; 1 by dougaj4</title>
		<link>http://newtonexcelbach.wordpress.com/2013/05/10/using-rc-design-functions-1/#comment-5522</link>
		<dc:creator><![CDATA[dougaj4]]></dc:creator>
		<pubDate>Wed, 15 May 2013 10:36:11 +0000</pubDate>
		<guid isPermaLink="false">http://newtonexcelbach.wordpress.com/?p=4838#comment-5522</guid>
		<description><![CDATA[The axial force is applied at the centroid of the concrete section, but if the section is cracked, or the reinforcement is not symmetrical, then the centroid of the reaction force is not at the centroid of the concrete section, so if the applied axial load is not zero this creates an additional moment.

If the axial force = N, applied moment = M, depth of NA from top face = Dna, and depth of section = D, then the total applied moment about the neutral axis = 
M + N(Dna - D/2)

If you use that revised moment you should find that M/C = EJ (where J = 2nd Moment of Area), for any value of axial load.]]></description>
		<content:encoded><![CDATA[<p>The axial force is applied at the centroid of the concrete section, but if the section is cracked, or the reinforcement is not symmetrical, then the centroid of the reaction force is not at the centroid of the concrete section, so if the applied axial load is not zero this creates an additional moment.</p>
<p>If the axial force = N, applied moment = M, depth of NA from top face = Dna, and depth of section = D, then the total applied moment about the neutral axis =<br />
M + N(Dna &#8211; D/2)</p>
<p>If you use that revised moment you should find that M/C = EJ (where J = 2nd Moment of Area), for any value of axial load.</p>
]]></content:encoded>
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	<item>
		<title>Comment on 5 Year Report by Omar Khan</title>
		<link>http://newtonexcelbach.wordpress.com/2013/02/18/5-year-report/#comment-5518</link>
		<dc:creator><![CDATA[Omar Khan]]></dc:creator>
		<pubDate>Mon, 13 May 2013 19:40:11 +0000</pubDate>
		<guid isPermaLink="false">http://newtonexcelbach.wordpress.com/?p=4688#comment-5518</guid>
		<description><![CDATA[wow cool, i just discovered this blog
.. was interested in vba drawned shapes]]></description>
		<content:encoded><![CDATA[<p>wow cool, i just discovered this blog<br />
.. was interested in vba drawned shapes</p>
]]></content:encoded>
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